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Quiz 415 C. Avalanche effect. D. Nonlinear output impedance. 20. The gain of a transistor in a common-emitter circuit is 100 at a frequency of 1000 Hz. The gain is 70.7 at 335 kHz. The gain drops to 1 at 210 MHz. The alpha cutoff is: A. 1 kHz. B. 335 kHz. C. 210 MHz. D. None of the above.

Problem 24-5 Suppose a bipolar-transistor amplifier has a dc collector input of 115 W and an ac power output of 65.0 W. What is the efficiency in percent Use the formula for the efficiency of a bipolar transistor amplifier expressed as a percentage: eff% = 100 Pout/PC = 100 65/115 = 100 0.565 = 56.5%. Problem 24-6 Suppose an FET amplifier is 60 percent efficient. If the power output is 3.5 W, what is the dc drain power input

Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.

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BIPOLAR TRANSISTORS BEHAVE AS THEY DO BECAUSE CURRENT VARIATIONS AT one P-N junction produce larger current variations at another. You ve seen a simplified picture of how this happens, and how the effect can be exploited to get current amplification. The bipolar transistor isn t the only way that semiconductors can be combined to get amplification effects. The other major category of transistor, besides the bipolar device, is the field-effect transistor or FET. There are two main types of FET: the junction FET (JFET) and the metal-oxide FET (MOSFET).

Plug in values to the formula for the efficiency of an FET amplifier expressed as a percentage. The resulting equation is solved as follows: 60 = 100 3.5/PD 60 = 350/PD 60/350 = 1/PD PD = 350/60 = 5.8 W

A JFET can have any of several different forms. They all work the same way: the current varies because of the effects of an electric field within the device. The workings inside a JFET can be likened to the control of water flow through a garden hose. Electrons or holes pass from the source (S) electrode to the drain (D). This results in a drain current, ID , that is generally the same as the source current, IS. This is analogous to the fact that the water comes out of a garden hose at the same rate it goes in (assuming that there aren t any leaks in the hose). The rate of flow of charge carriers that is, the current depends on the voltage at a regulating electrode called the gate (G). Fluctuations in gate voltage, EG, cause changes in the current through the channel, IS or ID. Small fluctuations in the control voltage EG can cause large variations in the flow of charge carriers through the JFET. This translates into voltage amplification in electronic circuits.

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Efficiency versus Class Class A amplifiers have efficiency figures from 25 percent to 40 percent, depending on the nature of the input signal and the type of transistor used. A good class AB1 amplifier is 35 percent to 45 percent efficient. A class AB2 amplifier, if well designed and properly operated, can be up to about 50 percent efficient. Class B amplifiers are typically 50 percent to 65 percent efficient. Class C amplifiers can have efficiency levels as high as 75 percent.

A simplified drawing of an N-channel JFET, and its schematic symbol, are shown in Fig. 23-1. The N-type material forms the channel, or the path for charge carriers. In the N-channel device, the majority carriers are electrons. The source is at one end of the channel, and the drain is at the other. You can think of electrons as being injected into the source and collected from the drain as they pass through the channel. The drain is positive with respect to the source.

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