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like a short circuit at high frequencies, whereas it behaves more like an open circuit at low frequencies Figure 434 depicts ZC (j ) in the complex plane, alongside ZR (j ) and ZL (j ) The impedance parameter de ned in this section is extremely useful in solving AC circuit analysis problems, because it will make it possible to take advantage of most of the network theorems developed for DC circuits by replacing resistances with complex-valued impedances The examples that follow illustrate how branches containing series and parallel elements may be reduced to a single equivalent impedance, much in the same way resistive circuits were reduced to equivalent forms It is important to emphasize that although the impedance of simple circuit elements is either purely real (for resistors) or purely imaginary (for capacitors and inductors), the general de nition of impedance for an arbitrary circuit must allow for the possibility of having both a real and an imaginary part, since practical circuits are made up of more or less complex interconnections of different circuit elements In its most general form, the impedance of a circuit element is de ned as the sum of a real part and an imaginary part: Z(j ) = R(j ) + j X(j ) (465)

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where R is called the AC resistance and X is called the reactance The frequency dependence of R and X has been indicated explicitly, since it is possible for a circuit to have a frequency-dependent resistance Note that the reactances of equations 460 and 464 have units of ohms, and that inductive reactance is always positive, while capacitive reactance is always negative The following examples illustrate how a complex impedance containing both real and imaginary parts arises in a circuit

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A practical capacitor can be modeled by an ideal capacitor in parallel with a resistor (Figure 435) The parallel resistance represents leakage losses in the capacitor and is usually quite large Find the impedance of a practical capacitor at the radian frequency = 377 rad/s How will the impedance change if the capacitor is used at a much higher frequency, say 800 MHz

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a. Are the loci linked b. If so, give the gene order, map distances, and coef cient of coincidence. Answer: The pattern of numbers among the eight offspring classes is the pattern we are used to seeing for linkage of three loci. We can tell from the two groups in largest numbers (the nonrecombinants uted, claret, curled and wild-type) that the alleles are in the coupling (cis) arrangement. If we compare either of the nonrecombinant classes with either of the double crossover classes ( uted and claret, curled), we see that the uted locus is in the center. For example, compare uted, a double crossover offspring, with the wild-type, a nonrecombinant; clearly, uted has the odd pattern.Thus the trihybrid female parent had the following arrangement of alleles: ca cu ca+ fl + cu+ A crossover in the ca region produces claret and uted, curled offspring, and a crossover in the cu region produces uted, claret and curled offspring. Counting the crossovers in each region, including the double crossovers in each, and then converting to percentages, yields a claret-to- uted distance of 35.0 map units (173 167 6 4) and a uted-to-curled distance of 6.0 map units (26 24 6 4). We expect 0.35 0.06 1,000 21 double crossovers, but we observed only 6 4 10. Thus, the coef cient of coincidence is 10/21 0.48.

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Known Quantities: C1 = 01 F = 01 10 6 F; R1 = 1 M Find: The equivalent impedance of the parallel circuit, Z1

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Substituting numerical values, we nd Z1 ( = 377) = 106 106 = 1 + j 377 106 01 10 6 1 + j 377

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= 26516 104 15443 The impedance of the capacitor alone at this frequency would be: ZC1 ( = 377) = 1 = 2653 103 /2 j 377 01 10 6

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