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Now this may be an improvement, but it is not optimal. The reason we wanted to allow the element to be stored in arbitrary positions in the first place was to simplify the insertion and deletion operations. We wanted to avoid having to shift segments of a[] back and forth. But the solution shown in Figure 3.4 merely transfers that obligation from a[] to k[]. If we had to insert the element 50, we could put it at position a[0] or a[2] or any place after a[6], but we would then have to insert its index into the index array k[] between k[2] and k[3] to keep track of the order of the elements. A better solution is to use the same array positions in the index array k[] as we are using in the data array a[]. Since the index array is keeping track of the correct order of the index numbers of the data elements, it can be used to do the same for the index numbers themselves.

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altogether. Fortunately, Java allows an even better solution, one that allows us to eliminate both arrays! Taking an object-oriented point of view, we see in Figure 3.8 a sequence of Node objects. Each object contains a data element and the address of the next object in the sequence. In Java, objects are directly accessed by their addresses. That s what an object reference is: the address of where the object is stored in memory. So by reinterpreting the meaning of address, as a memory address (i.e., object reference) instead of an array index, we can simplify the structure to the one shown in Figure 3.8. Here, the arrows represent object references (i.e., memory addresses).

Any signal x ( n ) may be decomposed into a sum of its even part, x,(n), and its odd part, x,(n), as follows:

x(n> = x d n )

CHAP. 3]

Now, instead of an array a[], we need only keep track of the single start reference. The Java runtime system does all the rest of the bookkeeping. The code is given in Example 3.3. EXAMPLE 3.3 A Node Class

(1.3)

x,(n) = ( x ( n )

In Figure 3.5, the index array k[] keeps track of the order of the elements in a[]. The starting index 3 is stored in k[0]. That begins the chain of indexes: k[0] = 3, k[3] = 5, k[5] = 1, k[1] = 4, k[4] = 6, k[6] = 0. The index 0 signals the end of the ordered sequence. The index sequence 0, 3, 5, 1, 4, 6 gives us the data elements in order: a[3] = 22, a[5] = 33, a[1] = 44, a[4] = 55, a[6] = 66. The extra variable free, shown Figure 3.5, saves the index of a free location in both the index array k[] and the data array a[]. The value 7 means that k[7] and a[7] should be used next. The implementation of an index array solves the problem of having to shift segments of array elements back and forth during deletions and insertions. For example, to insert x = 50 in Figure 3.5, we first traverse the sequence to find the index i of the largest element that is less than x: i = 1. Then just follow these three steps:

1 2 3

+x(-n))

x,(n) = i ( x ( n ) - x ( - n ) )

a[free] = x; k[free] = k[i]; k[i] = free++; // put x into the next free position // store the next index in that position in k[] // store the index of x in k[] and increment free

class Node { int data; Node next;

Definition: A complex signal is said to be conjugate symmetric3 if, for all n ,

x(n) = x*(-n)

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