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Arrays are inefficient for implementing dynamic sorted lists because the insert and delete operations require moving half the elements, on average. An index array is an array whose elements are index values into another array. Linked lists provide no direct access. To find the 100th element, you have to move sequentially through the first 99 elements. Insertion at the front of a linked list has to be done differently because the link to the new node is the start link; it is not p.next for any node p (unless you use a dummy head node). We had to define the linked lists backwards in the BigInt class because the digits of an integer are processed from right to left in the common arithmetic operations.

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EXAMPLE 2.7.3 Let us solve the following LCCDE for y ( n ) assuming zero initial conditions,

For example, if list is {22, 33, 44, 55, 66, 77, 88, 99}, then rotateLeft(list) will change list to {33, 44, 55, 66, 77, 88, 99, 22}. Note that no new nodes are created by this method.

for x ( n ) = &).

CHAP. 3]

We begin by taking the DTFT of each term in the difference equation:

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3.1 3.2 3.3 3.4 3.5 Arrays are inefficient for implementing dynamic sorted lists because the insert and delete operations require moving half the elements, on average. An index array is an array whose elements are index values into another array. Linked lists provide no direct access. To find the 100th element, you have to move sequentially through the first 99 elements. Insertion at the front of a linked list has to be done differently because the link to the new node is the

Because the DTFT of x ( n ) is X ( e j w ) = 1,

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void delete(int[] a, int n, int x) { int i = 0; // find the first index i for which a[i] > x: while (i < n && a[i] <= x) { ++i; } if (i < n-1) { System.arraycopy(a, i, a, i-1, n-i); } a[n-1] = 0; } int size(Node list) { int count = 0; while (list != null) { ++count; list = list.next; } return count; } int sum(Node list) { int sum = 0; while (list != null) { sum += list.data; list = list.next; } return sum; } void removeLast(Node list) { if (list == null || list.next == null) { throw new IllegalStateException(); } while (list.next.next != null) { list = list.next; } list.next = null; } Node copy(Node list) { if (list == null) { return null; } Node clone = new Node(list.data); for (Node p=list, q=clone; p.next != null; p=p.next, q=q.next) { q.next = new Node(p.next.data); } return clone; } Node sublist(Node list, int p, int q) { if (m < 0 || n < m) { throw new IllegalArgumentException(); } else if (n == m) { return null; } for (int i=0; i<m; i++) { list = list.next; }

the inverse DTFT of Y (ej") may be easily found using the linearity and shift properties,

start link; it is not p.next for any node p (unless you use a dummy head node).

The inverse of a system with unit sample response h(n) is a system that has a unit sample response g(n) such that

UML diagrams are independent of any implementing programming language They are used in object-oriented design to specify objects They should be easy to implement in Java, C++, or any other object-oriented programming language They provide a kind of pseudo-code for classes They specify the state (ie, fields) and the behavior (ie, methods) of an object without specifying how that behavior is accomplished UML diagrams include no executable code Specifying what an object can do without specifying how it does it is an abstraction It allows the design stage to be separated from the implementation stage of the software development It also facilitates modification of the software by allowing an implementation to be changed without affecting dependent modules As long as a method s behavior is unchanged, any invoking modules will be unaffected by a change in that method s implementation.

In terms of the frequency response, it is easy to see that, if the inverse of H ( e J m exists, it is equal to )

We had to define the linked lists backwards in the BigInt class because the digits of an integer are processed from right to left in the common arithmetic operations.

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